三数之和
// 1. 排序 2. 左右夹逼
func threeSum(nums []int) [][]int {
sort.Ints(nums)
res := make([][]int, 0)
for k:= 0; k < len(nums) - 2; k ++ {
if nums[k] > 0 {
break
}
if k> 0 && nums[k] == nums[k-1] {
continue
}
i := k + 1
j := len(nums) - 1
for i < j {
sum := nums[k] + nums[i] + nums[j]
if sum < 0 {
i ++
continue
}
if sum > 0 {
j --
continue
}
res = append(res, []int{nums[k] , nums[i], nums[j]})
for i < j && nums[i] == nums[i+1] {
i = i + 1
}
for i < j && nums[j] == nums[j-1] {
j = j -1
}
i++
j --
}
}
return res
}Last updated